Question

Write some identity of trignometery .....

Answer 1

1) sin^2 teta +cos^2 teta = 1
2) 1+ tan^ 2 teta = sec^2 teta
3) tanteta = sin ÷ cos
4) cot= cos ÷sin
5) 1+ cot ^2 = cosec ^2

Answer 2

TRIGNOMETERY

1 st Identity

Sin ( 90 - Q ) = Cos Q

PROVE =

As we know Sin Q = P/h

And in Figure

P = BC

and

H = AC

And Q = theta

So ,

Sin ( 90 - Q ) = BC/AC = Equation 1

AND COS Q

= BC/AC - Equation 2

From Equation 1 & 2

Sin ( 90 - Q ) = Cos Q

PROVED

2 = IDENTITY

Tan ( 90 - Q ) = Cot Q

PROVE

Tan ( 90 - Q ) = BC/AB - Equation 1

From Figure

Cot Q = BC/AB - Equation 2

From

Equation 1 and 2

Tan ( 90 - Q ) = Cot Q

PROVED

3 = IDENTITY

Cot ( 90 - Q ) = tan Q

PROVE

From figure

Cot ( 90 - Q ) = AB/BC - Equation 1

Tan Q = AB/BC - Equation 2

From equation 1 & 2

Cot ( 90 - Q ) = tan Q

PROVED

........

If there any mistake in my answer kindly say it to me as i am only in 9 i donot have more knowledge of Trignometery