write statement of Pythagoras theorem and show that 6, 8, and 10 are Pythagorean triplets
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according to Pythagoras theorem the square of hypotenuse is equal to the sum of square of perpendicular and base .
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according to pythagoras theorem (h)^2 =(b)^2 + (h)^2
(10)^2 = (8)^2 + (6)^2
100= 64 + 36
100 = 100
LHS = RHS
hence, proved
(10)^2 = (8)^2 + (6)^2
100= 64 + 36
100 = 100
LHS = RHS
hence, proved
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