Math, asked by amazedmusic3, 3 months ago

write step by step explanation try to write on a paper it will be convenient for both of us​

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Answered by vipashyana1
0

Step-by-step explanation:

 \frac{ \sqrt{7}  - 1}{ \sqrt{7}  + 1}  -  \frac{ \sqrt{7} + 1 }{ \sqrt{7}  - 1}  = a + b \sqrt{7}

 \frac{ { (\sqrt{7}  - 1)}^{2} -  { (\sqrt{7}  + 1)}^{2}  }{( \sqrt{7}  + 1)( \sqrt{7}  - 1)}  = a + b \sqrt{7}

 \frac{(7  + 1 - 2 \sqrt{7}) - (7 + 1 + 2 \sqrt{7} ) }{ \sqrt{7}( \sqrt{7}  - 1) + 1( \sqrt{7}  - 1) }  = a + b \sqrt{7}

 \frac{7 + 1 - 2 \sqrt{7 }  - 7 - 1 - 2 \sqrt{7} }{7 -  \sqrt{7} +  \sqrt{7}  - 1 }  = a + b \sqrt{7}

 \frac{7 - 7 + 1 - 1 - 2 \sqrt{7} - 2 \sqrt{7}  }{7 - 1 -  \sqrt{7}  +  \sqrt{7} }  =a  +  b\sqrt{7}

 \frac{( - 4 \sqrt{7}) }{6}  = a + b \sqrt{7}

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