Question

Write stock notations for the following: a) MnO₂ b) SnCl4​

Answer 1

Answer:

By applying the various rules for determining the oxidation number of different atoms in a compound, the oxidation number of each metallic element in the given compounds is as follows:

In HAuCI2,Au has +3; in Tl20,Tl has +1; in FeO,Fe has +2; in Fe2O2,Fe has +3; . in Cul,Cu has +1; in CuO,Cu has +2; in MnO,Mn has +2 while in Mn2O,Mn,has +4 oxidation state.

Therefore, these compounds may be represent as:

HAu(II)CI4,Tl2(1)O,Fe(II)O,Fe2(III)O3,Cu(II)O,Mn(II)O, and Mn(IV)O2.  

Explanation:

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Answer 2

Explanation:

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