write t2 and t3 for the AP. if a=-7 and d=-5
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Step-by-step explanation:
Given : For an A.P., if a = 11 and d= 1.5.
To find : The value of t_3t3 ?
Solution :
The nth term of A.P is given by,
t_n=a+(n-1)dtn=a+(n−1)d
Where, a=11 is the first term
d=1.5 is the common difference
n=3 is the number of terms
Substitute the value,
t_3=11+(3-1)1.5t3=11+(3−1)1.5
t_3=11+(2)1.5t3=11+(2)1.5
t_3=11+3t3=11+3
t_3=14t3=14
Therefore, the 3rd term is t_3=14t3=14 .
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