Question

write tan Q in term of sin Q?​

Answer 1

We know,

Sin²Q + Cos² Q = 1

=> Cos² Q = 1 - Sin² Q

=> Cos Q = √1 - Sin² Q

We also know that

$\tan(a) = \frac{ \sin(a) }{ \cos(a) }$

substituting the value of cos A from above.

$\tan(q) = \frac{ \sin \: q }{ \sqrt{1 - \sin {}^{2} q } }$

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