Question

write tan tita in terms of sin tita and cos tita​

Answer 1

refer to the given attachment....

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Answer 2

Answer:

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Step-by-step explanation:

$tan \theta = \displaystyle\frac{sin \theta}{cos \theta}$

$tan \theta = \displaystyle\frac{pependicular \: side}{adjacent \: side}$

$sin \theta = \displaystyle\frac{perpendicular}{hypotense} \\ \\ cos \theta = \displaystyle\frac{adjacent \: side}{hypotenuse}$

$So$

$\displaystyle\frac{sin\theta}{cos\theta} = \: \displaystyle\frac {perpendicular}{hypotenuse} \times \displaystyle\frac{hypotenuse}{adjacent}$

Hypotenuse gets cancelled:

$\displaystyle\frac{sin \theta}{cos \theta} = \displaystyle\frac{perpendicular}{adjacent}$

$We \: already \:know \: that, \\ \\ tan \theta = \displaystyle\frac{perpendicular}{adjacent}$

$So, tan\theta=\displaystyle\frac{sin\theta}{cos\theta}$