Math, asked by manepallivaasista, 1 year ago

write tan²A+tan⁴A in terms of sec​

Answers

Answered by Thûgłife
8

note it should be Sec^4A-sec^2A = tan^2A+tan^4 A )

Sec^4A-sec^2A

= sec^2 A ( sec^2 A - 1)

= (tan^2 A + 1) tan ^2 A

= tan ^4 A + tan ^2 A

Answered by rishu6845
0

Answer:

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