write ten number having 2 to 5 digit which are divisible by 10
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Step-by-step explanation:The numbers we have to be divisible by are: 2=21,3=31,4=22,5=51,6=21⋅31,8=23,9=32,10=51⋅212=21,3=31,4=22,5=51,6=21⋅31,8=23,9=32,10=51⋅21.
In order to include all these prime factors, any number divisible by all of these must be an integer multiple of 23⋅32⋅51=36023⋅32⋅51=360.
Five-digit numbers that are multiples of 360360 will be 360n360n where n≥⌈10000360⌉=28n≥⌈10000360⌉=28 and n≤⌊99999360⌋=277n≤⌊99999360⌋=277.
Those numbers are: 10080,10440,10800,…,99000,99360,99720
hope it helps you
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