Write ten rational numbers which lie between multiplicative inverse of 7/5 and additive inverse of -11/10
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Answer:
5/7 and 11/10
Step-by-step explanation:
a+b/2
5/7+11/10/2
lcm of 7and 10 =70
50+77/70/2
50+77/70into2
127/140
5/7<127/140<11/10
so by substituting this formula with 5/7 and 127/140 u will find another number
and again find another number with coming number and 5/7
if u have any doubts send me message or comment
I hope you understand
OK
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