Write ten such numbers, looking at their unit place, it can be concluded that they are not perfect squares.
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15382,33333,37407,14648,23782,27488,74837,74933,37373,79927
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Answer:
Ten such numbers = 12, 133, 187, 548, 522, 13, 17, 38, 47, 93.
Step-by-step explanation:
We know all the numbers are made up of only 10 numbers.
0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Every other number is made up of only these 10 numbers.
So,
We know that squares of these number is given by,
0² = 0
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
We can see that the perfect square of a number can only be ending with 0, 1, 4, 5, 6 and 9.
It never ends with the numbers 2, 3, 7 and 8.
Therefore, for getting 10 such numbers who we can identify by looking at their unit digits that they are not perfect squares can be any number ending with the digits 2, 3, 7 or 8.
So,
Ten such numbers can be 12, 133, 187, 548, 522, 13, 17, 38, 47, 93.
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