Write th dimensions of a nd b in th relation F=a√x+bt (t p squar) where F is force nd x is distance n t is time
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f = a√x + bt2, where [f] = [M L T −2], [x] = [L] and [t] = [T]. LHS is force. So both the terms on the RHS have the dimensions of force. [f] = [a √x] = [bt2] [f] = [a√x ...
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