Question

write the 11th term of the AP​

Answer 1

Step-by-step explanation:

12 √2 is the answer for above question

Answer 2

Answer:

11th term of an given AP is 12√2

Step-by-step explanation:

2√2 , 3√2 , 4√2 , ...

here, a = 2√2

d = √2

n = 11

$t_{n} = a + (n - 1)d$

$t_{n} = 2 \sqrt{2} + (11 - 1) \times \sqrt{2}$

$= 2 \sqrt{2} + 10 \times \sqrt{2}$

$= 2 \sqrt{2} + 10 \sqrt{2}$

$= 12 \sqrt{2}$