Write the 150th term of 2 4 6 8 10
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Given Sequence is
⇒2,4,6,8,10,,,,
⇒First term (a) = 2
⇒Common difference (d) = a₂-a₁ = 4 -2 = 2
To find
⇒Number of term 150
Formula
⇒Tₙ = a+(n-1)d
Now put the value
⇒T₁₅₀ = 2 + (150-1)×2
⇒T₁₅₀ = 2 + 149×2
⇒T₁₅₀ = 2+298
⇒T₁₅₀ = 300
Answer
⇒T₁₅₀ = 300
More Information
⇒Nth term = a+(n-1)d
⇒Sum = n/2{2a+(n-1)d}
or
⇒Sum = n/2(a+l)
where l = a + (n-1)d
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