Question

write the 9th term of the expansion of +((x/a)-(3a/x^2))^12

Answer 1

Answer:

(x/a-3/x²)¹² n=12, r=8,X=x/a,Y=3/x²

Step-by-step explanation:

Hey there !!! General term of a binomial expansion of the form (X+Y)ⁿ is = nCr(X)^n-r(Y)^r. So 9th term of (x/a-3/x²)¹² n=12, r=8,X=x/a,Y=3/x²