Write the acute angle θ satisfying√3 sin θ=cos θ.
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Answered by
3
SOLUTION :
Given : √3 sin θ = cos θ
√3 sin θ = cos θ
sin θ = cos θ / √3
sin θ / cos θ = 1 / √3
tan θ = tan 30°
[By using this identity , sin θ / cos θ = tan θ , tan 30° = 1 /√3]
On equating both sides,
θ = 30°
Hence, the acute angle θ is 30° .
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Answered by
1
you can solve it with this way also
÷ by 2 on both side
√3sin theta/2 - cos theta/2 = 0
sin(theta-30°) = 0
theta = 30°
÷ by 2 on both side
√3sin theta/2 - cos theta/2 = 0
sin(theta-30°) = 0
theta = 30°
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