Question

Write the additive inverse of 19/-6 and -2/3

Answer 1

Answer:

The additive inverse of 19/-6 is 19/6.

Step-by-step explanation:

We know that the sum of a number and its additive inverse is 0.

Let the additive inverse of 19/-6 be x, so that,

x + 19/-6 = 0

And we remember that in any fraction, if either numerator only or denominator only is negative, then the fraction is also negative. But if both are simultaneously negative, then the fraction is positive.

So, here, we can write 19/-6 as - 19/6.

Thus,

x + (- 19/6) = x - 19/6 = 0

This implies,

x = 19/6

Or we can do it in another way.

Consider what we considered earlier!

x + 19/-6 = 0

the additive inverse of -2/3 is

the additive inverse of -2/3 is2/3

In mathematics, the additive inverse of a number a is the number that, when added to a, yields zero. 

so, when we add 2/3 in -2/3 the result is zero

-2/3 + 2/3. = 0

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Answer 2

Step-by-step explanation:

answer is will be zero-0