Question

write the algebraic expressions :
The sum of squares of three consecutive numbers.​

Answer 1

Answer:

Sum of three consecutive numbers = 3 x smallest number + 1 + 2. Oh! that is the same as saying Sum of three consecutive numbers = 3 x smallest number + 3. By the distributive law of multiplication over addition, we can say that the Sum of three consecutive numbers = 3 x (smallest number + 1).

Answer 2

Answer:

The 3 consecutive integers are

n

n + 1

n + 2

Then

n2 + (n + 1)2 + (n + 2)2 = 194

n2 + (n2 + 2n + 1) + (n2 + 4n + 4) = 194

3n2 + 6n + 5 = 194

3n2 + 6n - 189 = 0

n2 + 2n - 63 = 0

(n - 7)(n + 9) = 0

n = 7 or -9

If n = 7, the 3 integers are 7, 8, and 9

If n = -9, the 3 integers are -9, -8, and -7

Step-by-step explanation:

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