Question

Write the algebraic form of 5 7 9 11

Answer 1

Answer:

2k+1

Step-by-step explanation:

The answer is 2k+1 where 'k' is an integer because,

(where k is 0)

2×0+1=1..........(1 is an odd no.)

(where k is 1)

2×1+1=3..........(3is an odd no.)

(where k is 2)

2×2+1=5.........(5 is an odd no.)

(where k is 3)

2×3+1=7..........(7 is an odd no.)

And so on........

Therefore, the algebraic form of odd numbers (1, 3, 5, 7......) is 2k+1.

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Answer 2

Answer:

2k+1

Step-by-step explanation:

The answer is 2k+1 where 'k' is any integer because,

(where k is 0)

2×0+1=1..........(1 is an odd no.)

(where k is 1)

2×1+1=3..........(3is an odd no.)

(where k is 2)

2×2+1=5.........(5 is an odd no.)

(where k is 3)

2×3+1=7..........(7 is an odd no.)

And so on........

Therefore, the algebraic form of odd numbers (1, 3, 5, 7......) is 2k+1.