write the amplitude of z = e(π÷3)i
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Step-by-step explanation:
z=(e
3−
4
iπ
)
3
=(e
3
.e
−
4
iπ
)
3
=e
9
.e
−
4
3iπ
=∣z∣e
iarg(z)
By comparing RHS and LHS we get
∣z∣=e
9
and arg(z)=
4
−3π
.
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