write the angle which is one- fifth of its complement
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Let the angle be x
complement of x is (90° − x)
One fifth of the complement angle is (90° − x)/5
Given x = (90° − x)/5
⇒ 5x = 90° − x
⇒ 6x = 90°
⇒ x = 90°/ 6 = 15°
Hence (90° − x) = (90° − 15°) = 75°
Thus the angles are 15° and 75°.
complement of x is (90° − x)
One fifth of the complement angle is (90° − x)/5
Given x = (90° − x)/5
⇒ 5x = 90° − x
⇒ 6x = 90°
⇒ x = 90°/ 6 = 15°
Hence (90° − x) = (90° − 15°) = 75°
Thus the angles are 15° and 75°.
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