Question

Write the AP when first term,a and common difference d are 4 and -3 respectively

Answer 1

Answer:

AP is generally represented in the form:

• a, a + d, a + 2d, a + 3d, ..... a + ( n - 1 ) d

Here,

• a = First Term
• d = Common Difference
• n = Number of terms

According to the question,

a = 4 and d = -3

Hence we get the AP as:

⇒ 4, 4 + ( -3 ), 4 + 2 ( -3 ), 4 + 3 ( -3 ), .... 4 + ( n - 1 ) -3

⇒ 4, ( 4 - 3 ), ( 4 - 6 ), ( 4 - 9 ), .... ( 4 + 3n - 3 )

⇒ 4, 1, -2, -5, .... 1 + 3n

This is the required AP.

Answer 2

The first term is given.

First term is 4.

Common difference is -3.

The common difference is the difference of all terms in an AP.

This means that the second term will differ from the first term by -3 and so will the third and second terms.

Let the second term be x.

It will differ by -3 from 4.

The difference is -3

So the AP is decreasing as difference is negative.

So next term will be:

x=4-3

which is 1.

The next term will be:x-3

=1-3

=-2

Thus the AP is 4,1,-2..............

Every term has a difference of -3.

Should I tell more clearly:

we start from a.

then a goes according to a+d.

here a=4 a+d=a+(-3)

=a-3

=4-3=1

next 1+d=1-3

=-2

next -2-3=-5

Answer:4,1,-2,-5................

Hope it helps.