Write the AP whose second term is 13 and the difference of the fourth term from the eighth term is 16
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Answer:
Step-by-step explanation:
a2=13
a8-a4=16
an=a+(n-1)d
a8=a+7d
a4=a+3d
a8-a4
=a+7d-(a+3d)=16
a+7d-a-3d=16
4d=16
d=4
a2=a+d
a+d=13
a+4=13
a=9
Using, a=9 and d=4,
AP=9,13,17,21.........
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