Math, asked by einstien3907, 9 months ago

Write the arithmetic progression when first term a and common difference of d are as follows:
(i)a=4,d=-3
(ii)a=-1,d=1/2
(iii)a=-1.5,d=-0.5

Answers

Answered by DeenaMathew
4
  • When the first term and common difference is given then by using following formula further terms can be determined :                                                                          

        a_{n} = a_{n-1} + d

  • where a_{n-1} is the given term or first term
  • d is common difference
  • a_{n} is the next term and n= 1, 2 ,3, 4, ...........

  • (i) a = 4, d= -3 ,                                                                              then second term will =  4+(-3) = 1,                                          third term =1 + (-3) = -2,                                                            fourth term = -2 +(-3) = -5,                                                        fifth term = -5 + (-3) = 8,    and so on ....
  • (ii) a = -1 , d= 1/2                                                                             second term = -1 + 1/2 = -1/2                                                   third term = -1/2 + 1/2 = 0                                                         fourth term = 0 + 1/2 = 1/2                                                       fifth term = 1/2 + 1/2 = 1,      and so on ....
  • (iii)a = -1.5, d = -0.5                                                                         second term = -1.5 + (-0.5) = -2                                               third term = -2 + (-0.5) = -2.5                                               fourth term = -2.5 + (-0.5) = -3                                               fifth term = -3 + (-0.5) = -3.5,   and so on....
Answered by isafsafiya
3

Given:-

  1. a = 4 and d = - 3
  2. a = 1 and d = 1/2
  3. a = -1.5 and d = -0.5

To find :-

  • aritjmetic progression witj first and common difference are follow

Solution:-

 1)a_{1} = 4 \\  \:  \:  \: d =  - 3 \\  \\ for \: a.p \\  \\ a_{1} = 4 \\  \\ a_{2} = a_{1} + d = 4 + ( - 3)  \\  \:  \:  \:  \: = 4 - 3  = 1 \\  \\ a_{3} = a_{2} + d = 1 + ( - 3) \\   \:  \:  \:  \:  \: = 1 - 3 =  - 2 \\  \\ a_{4} = a_{3} + d =  - 2 + ( - 3)  \\  \:  \:  \:  \:  \: =  - 2 - 3 =  - 5 \\  \\ a \: .p \\ 4 ,\:  \: 1, \:  - 2, \:  - 5

 2)a = 1 \\  \:  \:  \: d =  \frac{1}{2}  \\  \\ a_{1} = 1 \\  \\ a_{2} = a_{1} + d = 1 +  \frac{1}{2}  \\  \:  \:  \:  \:  \:    =  \frac{3}{2}  \\  \\ a_{3} = a_{2} + d =  \frac{3}{2}  +  \frac{1}{2}  \\  \\ \:  \:  \:  \:  \:   =  \frac{4}{2}  = 2 \\  \\ a_{4} = a_{3} + d = 2 +  \frac{1}{2}  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{5}{2}  \\  \\ a.p \: is \\ 1 ,\:  \:  \frac{3}{2}  ,\:  \:  \: 2, \:  \:  \:  \:  \:  \frac{5}{2},

a =  - 1.5 \\ d =  - 0.5 \\  \\ a_{1} =  - 1.5 \\  \\ a_{2} = a_{1} + d =  - 1.5 + ( - 0.5) \\  \:  \:  \:  \:  \:  =  - 2 \\  \\ a_{3} = a_{2} + d =  - 2 + ( - 0.5) \\  \:  \:  \:  \:  \:  =  - 2.5 \\  \\ a_{4} = a_{3} + d =  - 2.5 + ( - 0.5) \\   \:  \:  \:  \:  \:  =  - 3 \\  \\ a.p \:  \: is \\  - 1.5 ,\:  \:  \:  - 2 ,\:  \:  \:  \:  - 2.5, \:  \:  \:  \:  \:  \:  - 3

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