Write the balance chemical equation
Lead oxide + Carbon = Lead + Carbon dioxide. From the eqution, determine which reactant is oxidised and which is reduced.
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Word Equation
Lead (II) oxide + Carbon → Lead + Carbon dioxide
Formula Equation
2PbO (s) + C (s) → 2Pb (s) + CO2 (g)
Yellow lead (II) oxide (litharge) was mixed with powdered charcoal in a crucible. This was heated on a pipe-clay triangle on a tripod with a roaring bunsen flame and occasionally stirred. After 15 minutes small globules of molten lead were produced. Note : Carbon at first is partially oxidised to form carbon monoxide (PbO + C → Pb + CO) which then is involved in further reduction (PbO + CO → Pb + CO2). A mixture of gases would be expected with carbon dioxide being the dominant form.
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