Question

write the balance equation for reaction of al with dilute HCl and aqueous alkali​

Answer 1

Explanation:

Metals form respective salts when react with dilute acid. ... Reaction of aluminium with dilute hydrochloric acid: Aluminium chloride and hydrogen gas are formed. 2Al + 6HCl ⇨ 2AlCl3 + 3H2. Reaction of zinc with dilute sulphuric acid: Zinc sulphate and hydrogen gas are formed when zinc reacts with dilute sulphuric acid.

Answer 2

Answer:

1) Reaction of Al (Aluminium) with dilute HCl (Hydrochloric acid):

Aluminium reacts with dilute hydrochloric acid to produce aluminium chloride ($AlCl_3$) and evolves hydrogen gas ($H_2$).

The reaction is given below-

$2Al(s)+6HCl(dil.) ---- > 2AlCl_3(aq.) + 3H_2(g)$

2) Reaction of Al (Aluminium) with aqueous alkali:

Aluminium reacts with Sodium hydroxide (aqueous alkali) ($NaOH$) to produce sodium aluminate and hydrogen gas ($H_2$).

The reaction is given below-

$2Al(s)+6NaOH(aq.)---- > 2Na_3AlO_3(aq.)+3H_2(g)$

So, the above given reactions are the balanced equations for the reaction of Al with dilute HCl and aqueous alkali.

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