Question

Write the balanced chemical equation for the dissolution of magnesium bromide. What is the coefficient in front of the solvated anion?

Answer 1

$MgBr_2\rightarrow Mg^{2+}+2Br^-$

The coefiicient in front of the solvated anion is 2.

Explanation:

Magnesium bromide is made up of magnesium and bromine.

Magnesium atom will loose one electron to gain noble gas configuration and form magnesium cation with +2 charge.

Bromine atom will gain one electron to gain noble gas configuration and form bromide anion with -1 charge.

Thus magnesium bromide will be $MgBr_2$ as the charge on cation must balance the charge on anion.The dissolution will be as follows:

$MgBr_2\rightarrow Mg^{2+}+2Br^-$

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Answer 2

$\mathbb{ \ \ A\ N\ S\ W\ E\ R\: \: }$

The coefiicient in front of the solvated anion is 2.