write the balanced chemical equation for the following i) ethanoic acid reacts with ethanol in the presence of an acid. ii) ethanoic acid reacts with Sodium Bicarbonate
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a) CH3COOH + C2H5OH → CH3COOC2H5 + H2O
b) NaHCO3 + CH3COOH ——→ CH3COONa + H2O + CO2
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When ethanoic acid (Carboxylic acids) react with ethanol (alcohols) in presence of concentrated sulphuric acid as catalyst and form sweet smelling compounds called ester.
C2H5OH + CH3COOH ----> CH3COOC2H5 + H2O ethanol ethanoic acid ethyl ethanoate.
Ethanoic Acid + Sodium Carbonate -----> Sodium Ethanoate + Carbon Dioxide + Water.
In this case,
2CH3CO2H(aq) + Na2CO3(s) ------> 2CH3CO2Na(aq) + CO2(g) + H2O(l).
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C2H5OH + CH3COOH ----> CH3COOC2H5 + H2O ethanol ethanoic acid ethyl ethanoate.
Ethanoic Acid + Sodium Carbonate -----> Sodium Ethanoate + Carbon Dioxide + Water.
In this case,
2CH3CO2H(aq) + Na2CO3(s) ------> 2CH3CO2Na(aq) + CO2(g) + H2O(l).
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