Question

. Write the balanced chemical equations for the following reactions and identify the type of
reaction in each case.
(a) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to
form ammonia gas.
(b) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and
water.
(c) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of
concentrated H2SO4 .
(d) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases
heat and light.

Answer 1

Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to form ammonia gas. Answer: N2 + 3H2 + Catalyst/773 K ⇨ 2NH3 Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water. Answer: NaOH + CH3COOH ⇨ CH3COONa + H2O Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4 . Answer: C2H5OH + CH3COOH ⇨ CH3COOC2H5 + H2O Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases heat and light. Answer: C2H4 + 3O2 ⇨ 2CO2 + 2H2O + Heat + Light (a) and (c) are combination reactions, (b) is double displacement reaction and (d) is redox reaction.

Answer 2

Explanation:

. Write the balanced chemical equations for the following reactions and identify the type of

reaction in each case.

(a) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to

form ammonia gas.

(b) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and

water.

(c) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4 . ✔️

(d) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases

heat and light.