write the balanced eqation when calcium dropped in cold water
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Answered by
0
Answer:
Explanation:
Na,K,Ca react vigorously with water to liberate hydrogen gas forming corresponding hydroxides.
2Na
(s)
+2H
2
O
(l)
⟶2NaOH
(ag)
+H
2(ag)
↑
2K
(s)
+2H
2
O
(l)
⟶2KOH
(ag)
+H
2(g)
↑
Ca+2H
2
O
(l)
⟶Ca(OH)
2(ag)
+H
2(g)
↑
Answered by
0
Answer:
When a piece of Calcium is placed in water, then it form Calcium Hydroxide [Ca(OH) 2 ] and hydrogen gas (H 2 ).Ca+2H 2 O⟶Ca(OH) 2 +H 2↑Calcium react slowly with water.
hope it helps u....
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