Question

Write the balanced equation for the following
1. Al + HCL -- AlCl3 + H
2. Cu + No3 -- Cu(No3)2 + No2 + H2O

Answer 1

$\huge{\underline{\red{\rm{Answer:}}}}$

♦ Unbalanced Equation

$\sf Al + HCL$ $\longrightarrow$ $\sf AlCl_3 + H$

♦ Balanced Equation

$\sf Al + 3HCl$ $\longrightarrow$ $\sf AlCl_3 + 3H$

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♦ Unbalanced Equation

$\sf Cu_2 + HNo_3$ $\longrightarrow$ $\sf Cu(No3)2 + No2 + H2O$

♦ Balanced Equation

$\sf Cu_2$ + 8HNo3 $\longrightarrow$ $\sf Cu(No3)_2 + 4No_2 + H_2O$

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→ What is a balanced equation ?

Ans. A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.

•Things to keep in mind →

♣ Atoms of all the elements on both the sides should have same number of atoms.

♣ Balancing is done in order to fulfill the law of conservation of mass.

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According to the question, the reactions were balanced but here are the correct ones →

1) $\sf 2Al + 6HCl$ $\longrightarrow$ $\sf 2AlCl_3 + 3H_2$

2) $\sf Cu + 8 HNO_3$ $\longrightarrow$ $\sf 2Cu(NO3)_2 + 4NO_2 + 4H_20$

Answer 2

Answer:

1. Al + HCl ---> AlCl3 + H

We observe:

$\boxed{\begin{tabular}{c|c|c}\bf{Element} & \bf{LHS} & \bf{RHS}\\\cline{1-3}Al & 1 & 1\\\cline{1-3}H & 1 & 1\\\cline{1-3}Cl & 1 & 3\end{tabular}}$

Now, firstly we will balance chlorine.

Al + 3HCl ---> AlCl3 + H

Now, we need to balance hydrogen.

Al + 3HCl ---> AlCl3 + 3H

Now, the equation above is fully balanced.

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2. Cu + NO3 --> Cu(NO3)2 + NO2 + H2O

We observe:

$\boxed{\begin{tabular}{c|c|c}\bf{Element} & \bf{LHS} & \bf{RHS}\\\cline{1-3}Cu & 1 & 1\\\cline{1-3}N & 1 & 3\\\cline{1-3}O & 3 & 9 \\\cline{1-3}H & 0 & 2\end{tabular}}$

Now, firstly balancing the oxygen.

Cu + 3NO3 --> Cu(NO3)2 + NO2 + H2O

The other element which was unbalanced was nitrogen. It got balanced by adding 3 in LHS.

Now, for balancing hydrogen we need to add H2 in the left hand side.

Cu + NO3 +H2 --> Cu(NO3)2 + NO2 + H2O

Now, the equation above is fully balanced.

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The reactions given in the question has been balanced with the procedures above. But, the reaction doesn't seem to occur in the nature.

The correct reactions should be :

1. Al + Hcl -> AlCl3 + H2

2. Cu + (HNO3)2 -> Cu(No3)2 + No2 + H20

The balanced versions of the reactions, then will be :

1. 2Al + (3×2)Hcl -> 2AlCl3 + 3H2

2. Cu + 2(HNO3)2 -> Cu(No3)2 + 2No2 + 2H20

With the same procedure that is followed above to solve the question given by you should be followed to find the balance reaction of any given reaction.

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