Question

Write the balanced equation for the following chemical reaction Barium Chloride plus Aluminium Sulphate arrow Barium sulphate + aluminium chloride I want the answer step by step please fast

Answer 1

3BaCl2 + Al2(So4)3=3BaSo4+2AlCl3

Answer 2

Answer:

Step-by-step explanation:

Let us write the symbols and valency of the elements present in the given compounds:

Barium - Ba (2)

Aluminium - Al (3)

Chlorine - Cl (1)

Sulphate - SO4 (2)

Using the standard rules for writing the formula of the compounds, we can write the formula of the compounds as follows:

Barium Chloride - BaCl2

Aluminium Sulphate - Al2(SO4)3

Barium Sulphate - BaSO4

Aluminium chloride - AlCl3

Using the information given in the question, we can write the chemical equation as follows:

BaCl2 + Al2(SO4)3  → BaSO4 + AlCl3

Next step is balancing of chemical equation which is done to equalize the number of atoms of each element on both sides of the equation.

Let us count the number of each atoms on both sides of the equation and summarize in the following table

Element                                   LHS                                                RHS

Ba                                              1                                                       1

Cl                                               2                                                      3

Al                                               2                                                       1

S                                                3                                                       1

O                                                12 ( 4 x 3)                                         4

We can see from the above table that number of atoms of Ba is same on both sides. however number of all other elements are different. Hence we need to balance the number of atoms of these elements by putting appropriate numbers in front of the chemical formula in the equation.

Let us try to balance Cl. On LHS, there are 2 Cl atoms and on  RHS there are 3 Cl atoms. So, if we put 3 in front of  BaCl2 and 2 in front of AlCl3, the number of Cl atoms on both sides are 6. The equation is then

3 BaCl2 + Al2(SO4)3  → BaSO4 + 2 AlCl3

However we can clearly see that this disrupts the already balanced number of atoms of Barium. ( 3 on LHS; 1 on RHS )

Hence in order to balance Ba, we need to put 3 on RHS. The equation becomes:

3 BaCl2 + Al2(SO4)3  → 3 BaSO4 + 2 AlCl3

Now let us again count the number of atoms of each element and summarize it in a table.

Element                                   LHS                                                RHS

Ba                                              3                                                      3

Cl                                               6                                                      6

Al                                               2                                                       2

S                                                3                                                       3

O                                                12 ( 4 x 3)                                         12 (3 x 4 )

We can see the number of atoms of each and every element is same on both sides of the equation. Hence this would be our final balance equation.