Question

write the balanced equation for the reaction when potassium oxide is dissolved in water

Answer 1

Potassium oxide + water produces potassium hydroxide.
Potassium oxide is an ionic compound. The potassium has a charge of
K
+
and oxygen has a charge of
O
2
−
. We need 2 potassium ions to balance one oxide ion making the formula
K
2
O
.
Potassium hydroxide is an ionic compound. The potassium has a charge of
K
+
and hydroxide has a charge of
OH
−
. We need 1 potassium ion to balance one hydroxide ion making the formula
KOH
.
K
2
O
+
H
2
O
→
KOH
To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.
K
2
O
+
H
2
O
→
2
KOH

Answer 2

The balanced equation is :

$K_2O+H_2O\rightarrow 2KOH$

Explanation:

• Here, we need to write the balanced equation for the reaction when potassium oxide is dissolved in water.
• The reaction is :

$K_2O+H_2O\rightarrow 2KOH$

• Potassium oxide is an ionic compound. When Potassium oxide reacts with water, then potassium hydroxide will form. Potassium hydroxide is an ionic compound.

Learn more,

Balanced equation

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