write the balanced equation involved when sodium bicarbonate reacts with dilute hydrochloric acid
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Answered by
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hy friend ,
here,
NaHCO3 is sodium bicarbonate
HCl is hydrochloric acid
and CO2 is carbon dioxide
NaHCO3 + HCl ------------------------------------> NaCl + H2O + CO2
here,
NaHCO3 is sodium bicarbonate
HCl is hydrochloric acid
and CO2 is carbon dioxide
NaHCO3 + HCl ------------------------------------> NaCl + H2O + CO2
Answered by
0
ANSWER -
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Explanation:
2NaHCO3 + 2HCl ------> 2NaCl + 2H2O +2CO2
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