Question

write the balanced equation of reaction when acid extract is treated with bacl2 solution

Answer 1

H2SO4 + BaCl2------> BaSO4 + H2O

Answer 2

Explanation:

When barium chloride reacts with sulfuric acid then it results in the formation of barium sulfate which is a white precipitate and hydrogen chloride.

The reaction between barium chloride and sulfuric acid is as follows.

     $BaCl_{2} + H_{2}SO_{4} \rightarrow BaSO_{4}(aq) + HCl$

Number of atoms on reactant side are as follows.

• Ba = 1
• Cl = 2
• H = 2
• $SO_{4}$ = 1

Number of atoms on product side are as follows.

• Ba = 1
• Cl = 1
• H = 1
• $SO_{4}$ = 1

To balance the chemical equation, multiply HCl on product side by 2. Therefore, the balanced chemical equation will be as follows.

       $BaCl_{2} + H_{2}SO_{4} \rightarrow BaSO_{4}(aq) + 2HCl$