Question

Write the balanced equations for the following reactions and identify the type of reaction in

each case:

(a) Silver Nitrate (aq) + Potassium iodide (aq) → Silver iodide (s) + Potassium Nitrate (aq)

(b) Potassium Chlorate (s) → Potassium chloride (s) + Oxygen (g)

Answer 1

(a). AgNO3 (aq) + KI (aq) -> AgI (s) + KNO3 (aq)

In this case, the reaction is double displacement reaction.

(b). 2KClO3 (s) ----> 2KCl (s) + 3O2

In this case, the reaction is reduction reaction.

Hope this helps......

Answer 2

The balancing of a ‘chemical equation’ involves the balancing of all atoms at ‘both sides’ of the chemical equation. It means the ‘number of atoms’ must be same at both sides of the ‘chemical equation’.  

Hence here also to ‘balance the equation’ we need to check the ‘number of atoms’ at the ‘chemical equation.’

$\bold{a)\ \mathrm{AgNO}_{3}(\mathrm{aq})+\mathrm{KI}(\mathrm{aq}) \rightarrow \mathrm{KNO}_{3}(\mathrm{aq})+\mathrm{AgI}(\mathrm{s})}$$\bold{b)\ 2 \mathrm{KClO}_{3}(\mathrm{s}) \rightarrow 2 \mathrm{KCl}(\mathrm{s})+3 \mathrm{O}_{2}(\mathrm{g})}$