Question

Write the balanced overall equation for the following process (equation 3) and calculate ∆HoveralI.
(1) N2 (g) + O2(g) → 2NO(g) ∆H = 180.6 kJ
(2) 2NO(g) + O2(g) → 2NO2(g) ∆H = - 114.2 kJ
(3) ∆Hoverall=?

Answer 1

Answer:

rudjfjfjfjfjfjfjfkfkfkfkfkdkffkfkf

Answer 2

The balanced reaction is given below

• Adding both the equations -

N2 (g) + O2(g) → 2NO(g) ∆H = 180.6 kJ

2NO(g) + O2(g) → 2NO2(g) ∆H = - 114.2 kJ

• Final reaction will be -

N2 (g) + 2O2(g) → 2NO2(g)

∆H overall= 180.6 + ( - 114.2)

∆H overall= 66.4 kJ

• The calculation of overlap ∆H is in accordance with Hess's Law. The Hess's Law states that enthalpy of a reaction is sum of enthalpy of individual steps of reaction.

• Enthalpy is defined as "measure of heat in a system".

• In the reaction, N2 is nitrogen, O2 is oxygen, NO is nitric oxide and NO2 is nitrogen dioxide.