Question

write the base and power of each of the following exponents.
a) (-23/56)^6
b) (-6)^0


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Answer 1

(a) (-23/56)⁶

Here, (-23/56) is base and (6) is the exponent of  (-23/56)

Solving it further,

$\bf (-23/56)^{6} = \frac{(-23)\times(-23)\times(-23)\times(-23)\times(-23)\times(-23)}{56 \times 56 \times 56 \times 56 \times 56 \times 56 }$

Here we can use a trick,

There is a negative sign in 23 and the exponent is even.

Remember: For negative sign =

• When an exponent is an even number the result will be positive and
• When an exponent will be an odd number the result will be negative.

$\bf (-23/56)^{6} = \dfrac{148035889}{30840979456}$

And

(b) (-6)°

We know that

Any number having exponent '0' then the result will be 1

Hence,

(-6)⁰ = 1

Here are more examples,

(2/5)⁰ = 1

4⁰ = 1

(2347248)⁰ = 1

Answer 2

Given :-

$\sf \bigg(\dfrac{-23}{56}\bigg)^6$

$\sf \bigg(-6\bigg)^0$

To Find :-

Base and exponents

Solution :-

In 1

Base = -23/56

Exponent = 6

In 2

Base = -6

Exponent = 1

[Because in any number if power is 0 So, the number will be 1]