Write the cathode reaction in electrolysis of water
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In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g)
Answered by
1
Answer:
In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g)
In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is: Reduction at cathode: 2 H+(aq) + 2e− → H2(g)Cathode (reduction): 2 H2O(l) + 2e−
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