Question

write the cell reaction and calculate e m. f of the cell represented by Ni(s)|Ni2+(aq) (1M) ||sn2+(aq) (1M) |sn(s) E°ni=-0.25V,E°sn =-0.140V​

Answer 1

Answer:

-0.110V

Explanation:

E=Eo-(0.0591/n)log(Qc)

Log(Qc)= log(1/1)=0

Therefore E of cell =Eo

=(-0.140)-(-0.250)=-0.110V

Hope this answer helped you :)