Question

Write the cell reaction and calculate Eº cell of the following
electrochemical cell:
AllAl3+||Zn2+Izn
(s) (aq.) (aq.) (s)
(1M) (IM)
E°al = -1.66V
E°zn= – 0.76V​

Answer 1

Given that,

Cell potential of Al $E^{o}_{Al}=-1.66\ V$

Cell potential of Zn $E^{o}_{Zn}=-0.76\ V$

We know that,

Zinc is anode and silver is cathode.

We need to calculate the cell potential E⁰

Using formula of cell potential

$E^{o}_{cell}=E^{o}_{cathod}-E^{o}_{anode}$

Where, $E^{o}_{cathod}$ = cell potential of Al

$E^{o}_{anode}$ = cell potential of Zn

Put the value into the formula

$E^{o}_{cell}=-1.66-(-0.76)$

$E^{o}_{cell}=-0.9\ V$

Hence, The cell potential E⁰ is -0.9 V.