write the chemical equation for the reaction between propanoic acid and methanol in presence of sulphuric acid
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The reaction is between Propanoic acid(a carboxyllic acid) and methanol(an alcohol) in the presence of Sulphuric acid. So it is an esterification reaction. An ester and water are formed in the reaction. The reaction is
methanol is added to alcohol so that people don't drink it or abuse or smuggle it.
the reaction should take between ethanol and ethanoic acid(carboxylic acid not a type of another acid).
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CH3-CH2-COOH + CH3OH ---------> CH3-CH2-COOCH3 +H2O
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