Chemistry, asked by pankhudi, 1 year ago

write the chemical equation for the reaction between propanoic acid and methanol in presence of sulphuric acid

TPS: If you have any doubt in the answer, please ask.

Answers

Answered by TPS

The reaction is between Propanoic acid(a carboxyllic acid) and methanol(an alcohol) in the presence of Sulphuric acid. So it is an esterification reaction. An ester and water are formed in the reaction. The reaction is $C_2H_5COOH+CH_3OH \rightarrow C_2H_5COOCH_3+H_2O$

lfstone3: methanol is added to alcohol so that people don't drink it or abuse or smuggle it.

lfstone3: the reaction should take between ethanol and ethanoic acid(carboxylic acid not a type of another acid).

Answered by vlad

CH3-CH2-COOH + CH3OH ---------> CH3-CH2-COOCH3 +H2O

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