Write the chemical equation of the reaction in which the following changes have taken place with an example of each: (i) Change in colour (ii) Change in temperature (iii) Formation of precipitate answer fast =_=
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Explanation:
(i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. (iii) Formation of precipitate: Action of barium chloride on sodium sulphate
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Answer:
(i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. (iii) Formation of precipitate: Action of barium chloride on sodium sulphate
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