Question

WRITE THE CHEMICAL EQUATION OF THE REACTION IN WHICH THE FOLLOWING CHANGES HAVE TAKEN PLACE WITH AN EXAMPLE OF EACH----
A) CHANGE IN COLOUR.
B) CHANGE IN TEMPERATURE.
C) FORMATION OF PRECIPTATE.​

Answer 1

Answer:

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Explanation:

i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. Pb(NO3)2(aq)+2KI → PbI2(s)+2KNO3(aq) In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2 In this reaction, heat is evolved (iii) Formation of precipitate: Action of barium chloride on sodium sulphate. BaCl2(aq) +Na2SO4(aq) → BaSO4(s) +2NaCl(aq) BaSO4(s) - pptRead more on Sarthaks.com - https://www.sarthaks.com/84145/write-chemical-equation-reaction-example-which-following-change-taken-place-change-colour