Question

Write the chemical reaction taking place during discharging of lead accumulator​

Answer 1

Explanation:

The lead-acid storage cell gives an emf of 2 volt. ... In the discharged state, the lead (Pb) of the anode, and lead dioxide (PbO2) of the cathode are completely converted to lead sulphate (PbSO4). The water produced in the reaction dilutes the sulphuric acid.

Reaction:

At anode: (oxidation) Pb + SO42–→PbSO4(s) + 2e–

At anode: (oxidation) Pb + SO42–→PbSO4(s) + 2e–At cathode: (reduction) PbO2(s) + 4H++ SO42–+ 2e– → PbSO4(s) + 2H2O

At anode: (oxidation) Pb + SO42–→PbSO4(s) + 2e–At cathode: (reduction) PbO2(s) + 4H++ SO42–+ 2e– → PbSO4(s) + 2H2ONet cell reaction: Pb + PbO(s) + 4H+ + 2SO42– → 2PbSO4(s) + 2H2O

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