Science, asked by sachimeshram, 4 months ago

Write the chemical reactions.
1.Combustion reaction of propane (C3H8)
2.Sodium metal is dropped in n-propyl alcohol.
3.N-butyl alcohol is heated with concentrated sulphuric acid.
4.Sodium metal is dropped in ethanoic acid.

Answers

Answered by Anonymous
0

1)

2 C3H8 + 10O2---------------->   6CO2  +  8H2O

2)  

2Na +  2C3H7OH -----------> 2C3H7ONa   +  H2  ( Sodium Propoxide)

                           △

3)  C4H9OH -----------------> C4H8  +  H-OH (Butene and water)

                   conc. H2SO4

4)    2CH3COOH  + 2Na--------------> 2CH3COONa  +  H2

Answered by mohityadavji2008
0

Answer:

brainlist answer 1answer

The balanced chemical equation for the combustion of propane is: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g). C 3 H 8 ( g ) + 5 O 2 ( g ) → 3 C O 2 ( g ) + 4 H 2 O ( g ) . 2answerThe Reaction between Sodium Metal andEthanol. If a small piece of sodium is dropped into ethanol, it reacts steadily to give off bubbles of hydrogen gas and leaves a colorless solution of sodium ethoxide: \(CH_3CH_2ONa\). The anion component is an alkoxide 3answer the formation of product depend upon temperature 4answer if

Explanation:

it form sodium ethanote

2CH3COOH +na

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