Write the chemical reactions.
1.Combustion reaction of propane (C3H8)
2.Sodium metal is dropped in n-propyl alcohol.
3.N-butyl alcohol is heated with concentrated sulphuric acid.
4.Sodium metal is dropped in ethanoic acid.
Answers
1)
2 C3H8 + 10O2----------------> 6CO2 + 8H2O
2)
2Na + 2C3H7OH -----------> 2C3H7ONa + H2 ( Sodium Propoxide)
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3) C4H9OH -----------------> C4H8 + H-OH (Butene and water)
conc. H2SO4
4) 2CH3COOH + 2Na--------------> 2CH3COONa + H2
Answer:
brainlist answer 1answer
The balanced chemical equation for the combustion of propane is: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g). C 3 H 8 ( g ) + 5 O 2 ( g ) → 3 C O 2 ( g ) + 4 H 2 O ( g ) . 2answerThe Reaction between Sodium Metal andEthanol. If a small piece of sodium is dropped into ethanol, it reacts steadily to give off bubbles of hydrogen gas and leaves a colorless solution of sodium ethoxide: \(CH_3CH_2ONa\). The anion component is an alkoxide 3answer the formation of product depend upon temperature 4answer if
Explanation:
it form sodium ethanote
2CH3COOH +na
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