Chemistry, asked by amitsharma7775, 1 year ago

Write the chemical reactions for the different methods used for the reduction of aldehydes and ketones.

Answers

Answered by udeshya
1
REDUCTION OF ALDEHYDES AND KETONES

This page looks at the reduction of aldehydes and ketones by two similar reducing agents - lithium tetrahydridoaluminate(III) (also known as lithium aluminium hydride) and sodium tetrahydridoborate(III) (sodium borohydride).

Background to the reactions

The reducing agents

Despite the fearsome names, the structures of the two reducing agents are very simple. In each case, there are four hydrogens ("tetrahydido") around either aluminium or boron in a negative ion (shown by the "ate" ending).

The "(III)" shows the oxidation state of the aluminium or boron, and is often left out because these elements only ever show the +3 oxidation state in their compounds. To make the names shorter, that's what I shall do for the rest of this page.

REDUCTION OF ALDEHYDES AND KETONES

This page looks at the reduction of aldehydes and ketones by two similar reducing agents - lithium tetrahydridoaluminate(III) (also known as lithium aluminium hydride) and sodium tetrahydridoborate(III) (sodium borohydride).

Background to the reactions

The reducing agents

Despite the fearsome names, the structures of the two reducing agents are very simple. In each case, there are four hydrogens ("tetrahydido") around either aluminium or boron in a negative ion (shown by the "ate" ending).

The "(III)" shows the oxidation state of the aluminium or boron, and is often left out because these elements only ever show the +3 oxidation state in their compounds. To make the names shorter, that's what I shall do for the rest of this page.

Note:  It isn't important as far as the current page is concerned, but if you want to understand more about oxidation states (oxidation numbers), you will find them explained if you follow this link.

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The formulae of the two compounds are LiAlH4 and NaBH4.

Their structures are:



In each of the negative ions, one of the bonds is a co-ordinate covalent (dative covalent) bond using the lone pair on a hydride ion (H-) to form a bond with an empty orbital on the aluminium or boron.

Note:  Follow this link if you aren't happy about co-ordinate covalent (dative covalent) bonding.

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The overall reactions

The reduction of an aldehyde

You get exactly

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