write the co ordinate of the point p(x, y) which divides the line segment joining the point A(x, y) and (x2, y2) in the ratio m1:m2
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1
Step-by-step explanation:
internally in the ratio (m
1
:m
2
). (ie)
PB
AP
=
m
2
m
1
From the figure we know that \triangle AFP and \triangle PGB are similar.
PG
AF
=
BG
PF
=
PB
AP
=
m
2
m
1
Now take any two fractions,
PG
AF
=
m
2
m
1
⇒
x
2
−x
x−x
1
=
m
2
m
1
Doing Cross multiplication, x =
m
1
+m
2
m
1
x
2
+m
2
x
1
Then,
BG
PF
=
PB
AP
=
m
2
m
1
⇒
y
2
−y
y−y
1
=
m
2
m
1
Doing Cross multiplication, y =
m
1
+m
2
m
1
y
2
+m
2
y
1
solution
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