Write the co-ordinates of a point M which lies in the second quadrant and is at a distance of 6 units from both the axes.
Answers
Answered by
2
Answer:
The perpendicular distance from x -axis ,y -4units perpendicular distance from
y-axis,
x = 5units
∴(x,y)=(−5,4)
solution
Answered by
1
second quadrant:- (x-axis= '-' , y-axis= '+' )
so, the co-ordinates of the point M will be (-6,+6)
hope it's helpful...
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