Question

Write the coefficient of x² in(2x-5)
(2x²-3x+1)also write the number of terms and the degree.

Answer 1

Step-by-step explanation:

(2x-5) (2x^2-3x+1)

= 2x (2x^2-3x+1) - 5(2x^2-3x+1)

= 4x^3 - 6x^2 + 2x - 10x^2 + 15x - 5

= 4x^3 - 16x^2 + 17x - 5

Now, degree is 3 and

no. of terms are 4

coefficient of x^2 is -16 .

Hope it will help you....

Answer 2

Given,

A polynomial p(x) = (2x-5)(2x²-3x+1)

To find,

a) The coefficient of x² in p(x)

b) The number of terms in p(x)

c) the degree of p(x)

Solution,

We can simply solve this mathematical problem using the following process:

On simplifying the given polynomial p(x), we get;

p(x) = (2x-5)(2x²-3x+1)

= 2x(2x²-3x+1) - 5(2x²-3x+1)

= 4x^3 -6x^2 + 2x -10x^2 + 15x - 5

= 4x^3 -16x^2 + 17x - 5

= (4)x^3 + (-16)x^2 + (17)x + (-5)

Hence, p(x) has a total of 4 terms. The coefficient of x² in p(x) is equal to (-16) and the degree of p(x) is equal to 3.